题目

#include <bits/stdc++.h>
using namespace std;
#define int long long
#define pb push_back
#define fi first
#define se second
#define lson p << 1
#define rson p << 1 | 1
const int maxn = 1e6 + 5, inf = 1e9, maxm = 4e4 + 5;
const int N = sqrt(1e9) + 1;
 const int mod = 1e9 + 7;
// const int mod = 998244353;
//const __int128 mod = 212370440130137957LL;
// int a[505][5005];
// bool vis[505][505];

int a[maxn], b[maxn];
bool vis[maxn];
string s;
int n, m;

struct Node{
    int val, id;
    bool operator<(const Node &u)const{
        return val < u.val;
    }
};
// Node c[maxn];

int ans[maxn];
int pre[maxn];
vector<int> prime;

//long long ? maxn ?
void solve(){
    int res = 0;
    int q, k;
    cin >> n;
    // int mx = 0, mn = inf;
	for(int i = 1; i <= n; i++){
		cin >> a[i];
	}
    set<int> S;
    for(int i = 1; i <= n; i++){//先把sqrt(1e9)的素数筛出来，再进行质因数分解，不然会超时
        for(auto x : prime){
            if(a[i] % x == 0){
                if(S.count(x)){
                    cout << "Yes\n";
                    return;
                }
                S.insert(x);
                while(a[i] % x == 0){
                    a[i] /= x;
                }
            }
        }
        if(a[i] > 1){
            if (S.count(a[i])){
                cout << "Yes\n";
                return;
            }
            S.insert(a[i]);
        }
    }
    cout << "No\n";
}
    
signed main(){
    ios::sync_with_stdio(0);
    cin.tie(0);
    //素数筛
    for(int i = 2; i <= N; i++){
        if(!vis[i]){
            prime.pb(i);
        }
        for(int j = 2 * i; j <= N; j += i){
            vis[j] = 1;
        }
    }

    int T = 1;
    cin >> T;
    while (T--)
    {
        solve();
    }
    return 0;
}